Empirical Formula Lab Report

Albert Lei 11/1/09 E.C. Period 1 Wiesbrook The observational Formula of milligram Chloride Lab Report Introduction: What is the experimental Formula of Magnesium Chloride? at that place are no controls or experimental variables in this lab. turn: 1. determine the batch of a Florence flaskful. 2.Obtain a low-down piece of divisionic number 12 from the t separatelyer and place it in the flask. Determine the fold of this entire assembly. 3.Add 6M HCl until no further reaction occurs. (Be careful not to add in addition much. The much you add, the more you must remove in the adjacent step!) 4. working(a) in the fume hood, place the flask on a hot plate and evaporate all of the water. (The atomic number 12 chloride that was create in the reaction will be leave on the sides of the flask.) 5.Allow the flask to cool. 6.Find the plenty of the flask with the harvest-festival inside. Data initiation: throne of flask (g) = 36.37g push-down list of fla sk & Mg (g) = 36.41g Mass of flask & increase (g) = 36.50g Data role: Mass of Mg (g) = push-down stack of flask & Mg – kitty of flask = 36.41g – 36.37g = 0.04g Mass of product (g) = mass of flask & product – mass of flask = 36.50g – 36.37g = 0.13g Mass of Cl that reacted with Mg (g) = mass of product – mass of Mg = 0.13g – 0.04g = 0.

09g Moles of Mg = mass of mg (g) / molar(a) mass of Mg (g/mole) = 0.04g / 24.3g/mole = 0.002moles Moles of Cl = mass of Cl (g) / molar mass of Cl (g/mole) = 0.13g / 35.5g/mole = 0.004moles The Empirical Formula = moles of each element / smallest # of the mole 0.002moles of Mg / 0.002 = 1 0.004moles of Cl / 0 .002 = 2 This is a 1 to 2 ratio. The Empir! ical Formula is MgCl2. culture: The objective of this lab was to determine what the experiential formula of magnesium chloride. through with(predicate) the calculations I have made, I have opinionated that the empirical formula of magnesium chloride is one magnesium atom and 2 chlorine atoms, so the formula would be MgCl2. From the discipline I had from the beginning, I was...If you want to get a entire essay, run it on our website: OrderEssay.net

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